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Chemistry · Structure of atom
हिन्दीCalculate the wavelength (in nm) of the spectral line corresponding to the transition from \( n_2 = 4 \) to \( n_1 = 2 \) in the Balmer series of atomic hydrogen (\( R_H = 109677 \text{ cm}^{-1} \)).
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Correct answer · Option A
486 nm
Explanation
Using Rydberg formula \( \frac{1}{\lambda} = R_H (\frac{1}{2^2} - \frac{1}{4^2}) \), computing gives \( \lambda \approx 486 \text{ nm} \).
