Physics · Electrostatic Potential
हिन्दीConsider an electric dipole of dipole moment \( p \). At a large distance \( r \), the electrostatic potential at an angle \( \theta \) with the dipole axis is given by \( V = \frac{1}{4\pi\varepsilon_0} \frac{p \cos\theta}{r^2} \). What is the potential on the axial line of the dipole where \( \theta = 0^\circ \)?
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Correct answer · Option A
\( \frac{p}{4\pi\varepsilon_0 r^2} \)
Explanation
For \( \theta = 0^\circ \), \( \cos(0^\circ) = 1 \), so \( V = \frac{p}{4\pi\varepsilon_0 r^2} \).