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Chemistry · CHEMICAL BONDING AND MOLECULAR STRUCTURE
हिन्दीConsider the following isoelectronic pairs/species: \( \text{N}_2 \), \( \text{CO} \), \( \text{NO}^+ \), \( \text{F}_2 \), and \( \text{O}_2^{2-} \). Let \( S_1 \) be the sum of bond orders of \( \text{N}_2 \), \( \text{CO} \), and \( \text{NO}^+ \), and \( S_2 \) be the sum of bond orders of \( \text{F}_2 \) and \( \text{O}_2^{2-} \). What is the value of \( S_1 - 2S_2 \)?
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Correct answer · Option A
\( 5 \)
Explanation
Bond orders: \( \text{N}_2 = 3 \), \( \text{CO} = 3 \), \( \text{NO}^+ = 3 \), so \( S_1 = 3 + 3 + 3 = 9 \). For \( \text{F}_2 = 1 \) and \( \text{O}_2^{2-} = 1 \), so \( S_2 = 1 + 1 = 2 \). Therefore, \( S_1 - 2S_2 = 9 - 2(2) = 5 \). Wait, 9 - 4 = 5. Hence option 1 is 5.
