Mathematics · JEE | CONTINUITY AND DIFFERENTIABILITY
हिन्दीDifferentiate \( y = e^{\sin^{-1} x} \) with respect to \( x \).
View Answer & Solution
Correct answer · Option C
\( \frac{e^{\sin^{-1} x}}{\sqrt{1 - x^2}} \)
Explanation
Applying the chain rule, \( \frac{dy}{dx} = e^{\sin^{-1} x} \cdot \frac{1}{\sqrt{1 - x^2}} \).