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Physics · Electrostatic Potential
हिन्दीA capacitor of capacitance \( C_1 = 4\, \mu\text{F} \) is charged to \( 50\text{ V} \) and another capacitor \( C_2 = 6\, \mu\text{F} \) is charged to \( 100\text{ V} \). If they are connected together in parallel with plates of like polarity connected together, the final common potential difference across the combination is:
Correct answer · Option 2
\( 80\text{ V} \)
Explanation
Common potential \( V_{\text{common}} = \frac{C_1 V_1 + C_2 V_2}{C_1 + C_2} = \frac{4 \times 50 + 6 \times 100}{4 + 6} = \frac{200 + 600}{10} = 80\text{ V} \).
