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Chemistry · THERMODYNAMICS

हिन्दी

For the reaction \( 4\text{Fe}(s) + 3\text{O}_2(g) \rightarrow 2\text{Fe}_2\text{O}_3(s) \) at \( 298\text{ K} \), \( \Delta_r H^\circ = -1648\text{ kJ mol}^{-1} \) and \( \Delta_r S^\circ = -549.4\text{ J K}^{-1}\text{mol}^{-1} \). What is the total entropy change \( \Delta S_{\text{total}} \)?

  1. \( -5530\text{ J K}^{-1}\text{mol}^{-1} \)
  2. \( +4980.6\text{ J K}^{-1}\text{mol}^{-1} \)
  3. \( -4980.6\text{ J K}^{-1}\text{mol}^{-1} \)
  4. \( +6079.4\text{ J K}^{-1}\text{mol}^{-1} \)

Correct answer · Option 2

\( +4980.6\text{ J K}^{-1}\text{mol}^{-1} \)

Explanation

\( \Delta S_{\text{surr}} = -\frac{\Delta_r H^\circ}{T} = -\frac{-1648 \times 10^3}{298} = +5530\text{ J K}^{-1}\text{mol}^{-1} \). Hence, \( \Delta S_{\text{total}} = 5530 - 549.4 = +4980.6\text{ J K}^{-1}\text{mol}^{-1} \).
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