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Physics · MOTION IN A STRAIGHT LINE
हिन्दीMatch List-I with List-II for motion under gravity (ball thrown vertically upward with initial speed \( v_0 \)): List-I List-II A Time taken to reach peak height I \( v_0 \) B Maximum height reached above launch point II \( \frac{2 v_0}{g} \) C Total time of flight to return to launch level III \( \frac{v_0}{g} \) D Speed upon returning to launch level IV \( \frac{v_0^2}{2g} \) Choose the correct answer from the options given below:
Match List-I with List-II for motion under gravity (ball thrown vertically upward with initial speed \( v_0 \)):
| List-I | List-II | ||
|---|---|---|---|
| A | Time taken to reach peak height | I | \( v_0 \) |
| B | Maximum height reached above launch point | II | \( \frac{2 v_0}{g} \) |
| C | Total time of flight to return to launch level | III | \( \frac{v_0}{g} \) |
| D | Speed upon returning to launch level | IV | \( \frac{v_0^2}{2g} \) |
Choose the correct answer from the options given below:
Correct answer · Option 4
A-(III), B-(IV), C-(II), D-(I)
Explanation
Time to peak \( t = v_0 / g \) (A-III). Maximum height \( h_{\max} = v_0^2 / (2g) \) (B-IV). Total flight time \( T = 2v_0 / g \) (C-II). Speed returning to launch level equals initial speed \( v_0 \) (D-I).
