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Chemistry · PYQ NEET UG 2019(1)

हिन्दी

Which mixture of the solutions will lead to the formation of negatively charged colloidal [\( \text{AgI} \)]\( \text{I}^- \) sol?

  1. \( 50\text{ mL} \) of \( 1\text{ M}\text{ AgNO}_3 + 50\text{ mL} \) of \( 2\text{ M}\text{ KI} \)
  2. \( 50\text{ mL} \) of \( 2\text{ M}\text{ AgNO}_3 + 50\text{ mL} \) of \( 1.5\text{ M}\text{ KI} \)
  3. \( 50\text{ mL} \) of \( 0.1\text{ M}\text{ AgNO}_3 + 50\text{ mL} \) of \( 0.1\text{ M}\text{ KI} \)
  4. \( 50\text{ mL} \) of \( 1\text{ M}\text{ AgNO}_3 + 50\text{ mL} \) of \( 1.5\text{ M}\text{ KI} \)

Correct answer · Option 1

\( 50\text{ mL} \) of \( 1\text{ M}\text{ AgNO}_3 + 50\text{ mL} \) of \( 2\text{ M}\text{ KI} \)

Explanation

For a negatively charged [\( \text{AgI} \)]\( \text{I}^- \) sol, iodide ions (\( \text{I}^- \)) must be in excess, which occurs when moles of \( \text{KI} \) exceed moles of \( \text{AgNO}_3 \). In option 1, moles of \( \text{KI} = 50 \times 2 = 100\text{ mmol} \) and \( \text{AgNO}_3 = 50 \times 1 = 50\text{ mmol} \).
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