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Chemistry · PYQ NEET UG 2019(2)
हिन्दीThe molar solubility of \( \mathrm{CaF_2} \) \( (\mathrm{K_{sp}} = 5.3 \times 10^{-11}) \) in \( 0.1 \) \( \mathrm{M} \) solution of \( \mathrm{NaF} \) will be
Correct answer · Option 4
\( 5.3 \times 10^{-9} \) \( \mathrm{mol\,L^{-1}} \)
Explanation
\( \mathrm{K_{sp}} = [\mathrm{Ca^{2+}}][\mathrm{F^-}]^2 = s \times (0.1 + 2s)^2 \approx s \times (0.1)^2 = 5.3 \times 10^{-11} \), giving \( s = 5.3 \times 10^{-9} \) \( \mathrm{mol\,L^{-1}} \).
