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Physics · SYSTEMS OF PARTICLES AND ROTATIONAL MOTION
हिन्दीA lever of length \( 2.4\,\text{m} \) has its fulcrum placed at a distance of \( 40\,\text{cm} \) from the load end. An effort of \( 50\,\text{N} \) is applied at the other end to keep the lever in horizontal equilibrium. The load lifted by the lever and its mechanical advantage (M.A.) are, respectively:
Correct answer · Option 1
250 N and 5
Explanation
Load arm \( d_1 = 0.4\,\text{m} \). Total length \( 2.4\,\text{m} \), so effort arm \( d_2 = 2.4 - 0.4 = 2.0\,\text{m} \). Mechanical Advantage \( \text{M.A.} = \frac{d_2}{d_1} = \frac{2.0}{0.4} = 5 \). Load \( F_1 = \text{M.A.} \times F_2 = 5 \times 50 = 250\,\text{N} \).
