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Physics · MOTION IN A PLANE
हिन्दीA particle moves along a semi-circular path of radius \( R = 8\text{ m} \) from point A to point B. From point B, it turns and moves along a straight line segment of length \( 12\text{ m} \) perpendicular to the diameter AB. What is the magnitude of the total displacement of the particle from its initial position A?
Correct answer · Option 2
\( 20\text{ m} \)
Explanation
The displacement along the diameter AB is \( 2R = 16\text{ m} \). The perpendicular displacement is \( 12\text{ m} \). Total displacement magnitude \( = \sqrt{16^2 + 12^2} = \sqrt{256 + 144} = \sqrt{400} = 20\text{ m} \).
