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Chemistry · PYQ NEET UG 2016(2)
हिन्दीThe percentage of pyridine (\( \mathrm{C_5H_5N} \)) that forms pyridinium ion \( \mathrm{C_5H_5NH^+} \) in a \( 0.10\ \mathrm{M} \) aqueous pyridine solution is ________. (\( \mathrm{K_b} \) for \( \mathrm{C_5H_5N} = 1.7 \times 10^{-9} \))
Correct answer · Option 3
0.013 %
Explanation
Degree of dissociation \( \alpha = \sqrt{\frac{K_b}{C}} = \sqrt{\frac{1.7 \times 10^{-9}}{0.10}} = 1.3 \times 10^{-4} \). Percentage dissociation = \( 1.3 \times 10^{-4} \times 100\% = 0.013\% \).
