In a cross between a male and female, both heterozygous for sickle cell anaemia gene, what percentage of the progeny will be diseased?

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Correct answer · Option D

25%

Cross: Hb^A Hb^S × Hb^A Hb^S gives Hb^A Hb^A (25% normal), Hb^A Hb^S (50% carrier), Hb^S Hb^S (25% diseased).

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