OnlineCBT
Physics · MOTION IN A STRAIGHT LINE
हिन्दीA bullet entering a wooden block with an initial velocity of \( 100\text{ m s}^{-1} \) comes to rest after penetrating a distance of \( 0.1\text{ m} \). Assuming uniform retardation, what is the magnitude of the deceleration of the bullet?
Correct answer · Option 4
\( 5 \times 10^4\text{ m s}^{-2} \)
Explanation
Using \( v^2 = v_0^2 + 2ax \), we get \( 0 = (100)^2 + 2a(0.1) \implies 0.2a = -10000 \implies a = -50000\text{ m s}^{-2} \). Magnitude of deceleration = \( 5 \times 10^4\text{ m s}^{-2} \).
