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Physics · PYQ NEET UG 2020

हिन्दी

The average thermal energy for mono-atomic gas is: (\( k_B \) is Boltzmann constant and T, absolute temperature)

  1. A
    \( \frac{3}{2} k_B T \)
  2. B
    \( \frac{5}{2} k_B T \)
  3. C
    \( \frac{7}{2} k_B T \)
  4. D
    \( \frac{1}{2} k_B T \)
View Answer & Solution

Correct answer · Option A

\( \frac{3}{2} k_B T \)

Explanation

For a mono-atomic gas, the number of degrees of freedom is 3. By the law of equipartition of energy, average thermal energy = \( \frac{3}{2} k_B T \).
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