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Physics · SYSTEMS OF PARTICLES AND ROTATIONAL MOTION

हिन्दी

A light horizontal rod AB of length \( 2a \) is subjected to three parallel vertical forces: \( 2F \) downward at end A, \( F \) downward at end B, and an upward force \( 3F \) at a point C at distance \( x \) from end A. For the system to be in complete mechanical equilibrium, the value of \( x \) must be:

  1. \( \frac{2a}{3} \)
  2. \( \frac{a}{3} \)
  3. \( a \)
  4. \( \frac{4a}{3} \)

Correct answer · Option 1

\( \frac{2a}{3} \)

Explanation

Translational equilibrium: \( 3F - 2F - F = 0 \) is satisfied. For rotational equilibrium, take torque about A: \( (3F)(x) - F(2a) = 0 \implies 3Fx = 2Fa \implies x = \frac{2a}{3} \).
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