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Physics · UNITS AND MEASUREMENT
हिन्दीVelocity \( v \) of a wave on a stretched string depends on tension \( F \) and mass per unit length \( \mu \). The correct relation between \( v \), \( F \), and \( \mu \) obtained by dimensional analysis is:
Correct answer · Option 1
\( v = k \sqrt{\frac{F}{\mu}} \)
Explanation
Let \( v = k F^a \mu^b \). Equating dimensions \( [\text{L T}^{-1}] = [\text{M L T}^{-2}]^a [\text{M L}^{-1}]^b \) gives \( a = 1/2 \) and \( b = -1/2 \), so \( v = k \sqrt{\frac{F}{\mu}} \).
