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Physics · PYQ NEET UG 2016(2)
हिन्दीIf an electron in a hydrogen atom jumps from the \( 3^{\text{rd}} \) orbit to the \( 2^{\text{nd}} \) orbit, it emits a photon of wavelength \( \lambda \). When it jumps from the \( 4^{\text{th}} \) orbit to the \( 3^{\text{rd}} \) orbit, the corresponding wavelength of the photon will be
Correct answer · Option 4
\( \frac{20}{7}\lambda \)
Explanation
Using Rydberg formula \( \frac{1}{\lambda} = R (\frac{1}{n_1^2} - \frac{1}{n_2^2}) \), for 3 to 2 transition \( \frac{1}{\lambda} = R(\frac{1}{4} - \frac{1}{9}) = \frac{5R}{36} \). For 4 to 3 transition \( \frac{1}{\lambda'} = R(\frac{1}{9} - \frac{1}{16}) = \frac{7R}{144} \). Taking ratio gives \( \lambda' = \frac{20}{7}\lambda \).
