Physics · PYQ NEET UG 2023
हिन्दीIn a plane electromagnetic wave travelling in free space, the electric field component oscillates sinusoidally at a frequency of \( 2.0 \times 10^{10}\text{ Hz} \) and amplitude \( 48\text{ V m}^{-1} \). Then the amplitude of oscillating magnetic field is : (Speed of light in free space \( = 3 \times 10^8\text{ m s}^{-1} \))
Correct answer · Option 4
\( 1.6 \times 10^{-7}\text{ T} \)
Explanation
Amplitude of magnetic field \( B_0 = \frac{E_0}{c} = \frac{48}{3 \times 10^8} = 1.6 \times 10^{-7}\text{ T} \).