OnlineCBT
Chemistry · EQUILIBRIUM
हिन्दीMatch List-I (Equilibrium Reaction) with List-II (Relationship between \( K_p \) and \( K_c \)): List-I List-II A \( \text{H}_2(\text{g}) + \text{I}_2(\text{g}) \rightleftharpoons 2\text{HI}(\text{g}) \) I \( K_p = K_c (RT)^{-2} \) B \( \text{N}_2(\text{g}) + 3\text{H}_2(\text{g}) \rightleftharpoons 2\text{NH}_3(\text{g}) \) II \( K_p = K_c \) C \( 2\text{NOCl}(\text{g}) \rightleftharpoons 2\text{NO}(\text{g}) + \text{Cl}_2(\text{g}) \) III \( K_p = K_c (RT)^{-1} \) D \( 2\text{SO}_2(\text{g}) + \text{O}_2(\text{g}) \rightleftharpoons 2\text{SO}_3(\text{g}) \) IV \( K_p = K_c (RT)^1 \) Choose the correct answer from the options given below:
Match List-I (Equilibrium Reaction) with List-II (Relationship between \( K_p \) and \( K_c \)):
| List-I | List-II | ||
|---|---|---|---|
| A | \( \text{H}_2(\text{g}) + \text{I}_2(\text{g}) \rightleftharpoons 2\text{HI}(\text{g}) \) | I | \( K_p = K_c (RT)^{-2} \) |
| B | \( \text{N}_2(\text{g}) + 3\text{H}_2(\text{g}) \rightleftharpoons 2\text{NH}_3(\text{g}) \) | II | \( K_p = K_c \) |
| C | \( 2\text{NOCl}(\text{g}) \rightleftharpoons 2\text{NO}(\text{g}) + \text{Cl}_2(\text{g}) \) | III | \( K_p = K_c (RT)^{-1} \) |
| D | \( 2\text{SO}_2(\text{g}) + \text{O}_2(\text{g}) \rightleftharpoons 2\text{SO}_3(\text{g}) \) | IV | \( K_p = K_c (RT)^1 \) |
Choose the correct answer from the options given below:
Correct answer · Option 1
A-(II), B-(I), C-(IV), D-(III)
Explanation
For \( \text{H}_2 + \text{I}_2 \rightleftharpoons 2\text{HI} \), \( \Delta n = 0 \implies K_p = K_c \) (II); for \( \text{N}_2 + 3\text{H}_2 \rightleftharpoons 2\text{NH}_3 \), \( \Delta n = -2 \) (I); for \( 2\text{NOCl} \rightleftharpoons 2\text{NO} + \text{Cl}_2 \), \( \Delta n = +1 \) (IV); for \( 2\text{SO}_2 + \text{O}_2 \rightleftharpoons 2\text{SO}_3 \), \( \Delta n = -1 \) (III).
