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Chemistry · Structure of atom

हिन्दी

Calculate the wavelength of light emitted when an electron in a hydrogen atom undergoes transition from an energy level with \( n = 4 \) to an energy level with \( n = 2 \).

  1. \( 486\text{ nm} \)
  2. \( 656\text{ nm} \)
  3. \( 121\text{ nm} \)
  4. \( 434\text{ nm} \)

Correct answer · Option 1

\( 486\text{ nm} \)

Explanation

Using Rydberg formula \( \frac{1}{\lambda} = R_H (\frac{1}{2^2} - \frac{1}{4^2}) \), we get \( \lambda = 4.86 \times 10^{-7}\text{ m} = 486\text{ nm} \).
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