Chemistry · Structure of atom
हिन्दीCalculate the wavelength of light emitted when an electron in a hydrogen atom undergoes transition from an energy level with \( n = 4 \) to an energy level with \( n = 2 \).
Correct answer · Option 1
\( 486\text{ nm} \)
Explanation
Using Rydberg formula \( \frac{1}{\lambda} = R_H (\frac{1}{2^2} - \frac{1}{4^2}) \), we get \( \lambda = 4.86 \times 10^{-7}\text{ m} = 486\text{ nm} \).