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Physics · WORK, ENERGY AND POWER
हिन्दीReferring to the force-displacement graph shown below, an applied force F acts on a block moving along a straight line on a rough horizontal surface against a constant friction force \( f = -50 N \). The total net work done on the block over the entire \( 20 m \) distance is:
Correct answer · Option 4
\( 750\text{ J} \)
Explanation
From the graph, work by applied force \( W_F = (100 \times 10) + \frac{1}{2}(100 + 50)(10) = 1000 + 750 = 1750\text{ J} \). Work by friction \( W_f = (-50)(20) = -1000\text{ J} \). Net work \( = 1750 - 1000 = 750\text{ J} \).
