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Chemistry · PYQ NEET UG 2018
हिन्दीThe solubility of \( \mathrm{BaSO_4} \) in water is \( 2.42 \times 10^{-3} \text{ g L}^{-1} \) at \( 298 \text{ K} \). The value of its solubility product \( (\mathrm{K_{sp}}) \) will be (Given : molar mass of \( \mathrm{BaSO_4} = 233 \text{ g mol}^{-1} \))
Correct answer · Option 1
\( 1.08 \times 10^{-10} \text{ mol}^2 \text{ L}^{-2} \)
Explanation
Molar solubility \( s = \frac{2.42 \times 10^{-3}}{233} = 1.04 \times 10^{-5} \text{ mol L}^{-1} \). \( K_{sp} = s^2 = (1.04 \times 10^{-5})^2 \approx 1.08 \times 10^{-10} \text{ mol}^2 \text{ L}^{-2} \).
