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Physics · GRAVITATION

हिन्दी

In the given diagram, a point mass \( m \) is located at depth \( d \) from the Earth's surface. What fraction of the Earth's total mass \( M_E \) contributes to the gravitational force acting on this mass, assuming uniform density?

  1. \( \frac{R_E - d}{R_E} \)
  2. \( (\frac{R_E - d}{R_E})^2 \)
  3. \( (\frac{R_E - d}{R_E})^3 \)
  4. \( (1 - \frac{d^3}{R_E^3}) \)

Correct answer · Option 3

\( (\frac{R_E - d}{R_E})^3 \)

Explanation

Only the inner sphere of radius \( (R_E - d) \) exerts a net gravitational force. For uniform density, its mass is \( M_s = M_E (\frac{R_E - d}{R_E})^3 \).
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