Chemistry · Structure of atom
हिन्दीWhat is the de Broglie wavelength associated with an electron moving in an electron microscope with a velocity of \( 1.6 \times 10^6\text{ ms}^{-1} \)?
Correct answer · Option 2
\( 4.55 \times 10^{-11}\text{ m} \)
Explanation
Using \( \lambda = \frac{h}{mv} = \frac{6.626 \times 10^{-34}}{9.1 \times 10^{-31} \times 1.6 \times 10^6} = 4.55 \times 10^{-11}\text{ m} \).