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Physics · PYQ NEET UG 2019(2)

हिन्दी

A particle of mass \( 5m \) at rest suddenly breaks on its own into three fragments. Two fragments of mass \( m \) each move along mutually perpendicular direction with speed \( v \) each. The energy released during the process is,

  1. \( \frac{4}{3}mv^2 \)
  2. \( \frac{3}{5}mv^2 \)
  3. \( \frac{5}{3}mv^2 \)
  4. \( \frac{3}{2}mv^2 \)

Correct answer · Option 1

\( \frac{4}{3}mv^2 \)

Explanation

Mass of third fragment is \( 3m \). By conservation of momentum, \( p_3 = \sqrt{(mv)^2 + (mv)^2} = \sqrt{2}mv \). Final kinetic energy \( K_f = \frac{1}{2}mv^2 + \frac{1}{2}mv^2 + \frac{(\sqrt{2}mv)^2}{2(3m)} = mv^2 + \frac{1}{3}mv^2 = \frac{4}{3}mv^2 \).
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