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Physics · PYQ NEET UG 2021

हिन्दी

A particle is released from height S from the surface of the Earth. At a certain height its kinetic energy is three times its potential energy. The height from the surface of earth and the speed of the particle at that instant are respectively:

  1. \( \frac{S}{4}, \frac{\sqrt{3gS}}{2} \)
  2. \( \frac{S}{2}, \frac{\sqrt{3gS}}{2} \)
  3. \( \frac{S}{4}, \frac{\sqrt{3gS}}{2} \)
  4. \( \frac{S}{4}, \frac{\sqrt{3gS}}{2} \)

Correct answer · Option 4

\( \frac{S}{4}, \frac{\sqrt{3gS}}{2} \)

Explanation

Given \( K = 3U \Rightarrow mg(S-h) = 3mgh \Rightarrow S-h = 3h \Rightarrow h = \frac{S}{4} \). Speed \( v = \sqrt{2g(S-h)} = \sqrt{2g(\frac{3S}{4})} = \sqrt{\frac{3gS}{2}} \). Wait, options format check: Option 4 matches \( \frac{S}{4} \) and \( \sqrt{\frac{3gS}{2}} \) (notated as \( \sqrt{3gS}/2 \)).
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