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Chemistry · THERMODYNAMICS

हिन्दी

For a reaction in equilibrium, the relationship between the standard Gibbs energy change \( \Delta_r G^\circ \) and the equilibrium constant \( K \) is given by:

  1. \( \Delta_r G^\circ = +2.303 RT \log K \)
  2. \( \Delta_r G^\circ = -2.303 RT \log K \)
  3. \( \Delta_r G^\circ = -RT \log K \)
  4. \( \Delta_r G^\circ = -\frac{RT}{2.303} \ln K \)

Correct answer · Option 2

\( \Delta_r G^\circ = -2.303 RT \log K \)

Explanation

At equilibrium, \( \Delta_r G = 0 = \Delta_r G^\circ + RT\ln K \implies \Delta_r G^\circ = -RT\ln K = -2.303 RT\log K \).
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