Physics · PYQ NEET UG 2021
हिन्दीA body is executing simple harmonic motion with frequency 'n', the frequency of its potential energy is:
Correct answer · Option 1
2n
Explanation
Potential energy in SHM is given by \( U = \frac{1}{2} m \omega^2 x^2 = \frac{1}{2} m \omega^2 A^2 \sin^2(\omega t) \). Since it depends on \( \sin^2(\omega t) = \frac{1-\cos(2\omega t)}{2} \), the frequency of potential energy is \( 2n \).