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Physics · PYQ NEET UG 2021

हिन्दी

A body is executing simple harmonic motion with frequency 'n', the frequency of its potential energy is:

  1. 2n
  2. 3n
  3. 4n
  4. n

Correct answer · Option 1

2n

Explanation

Potential energy in SHM is given by \( U = \frac{1}{2} m \omega^2 x^2 = \frac{1}{2} m \omega^2 A^2 \sin^2(\omega t) \). Since it depends on \( \sin^2(\omega t) = \frac{1-\cos(2\omega t)}{2} \), the frequency of potential energy is \( 2n \).
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