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Chemistry · EQUILIBRIUM
हिन्दीA sparingly soluble salt \( \text{A}_2\text{X}_3 \) has a solubility product \( K_{sp} = 1.08 \times 10^{-23} \) at 298 K. The molar concentration of \( \text{A}^{3+} \) ions in its saturated aqueous solution is:
Correct answer · Option 4
\( 2.0 \times 10^{-5}\text{ M} \)
Explanation
For \( \text{A}_2\text{X}_3 \), \( K_{sp} = (2S)^2(3S)^3 = 108S^5 \). Given \( 108S^5 = 1.08 \times 10^{-23} \implies S^5 = 10^{-25} \implies S = 1.0 \times 10^{-5}\text{ M} \). Therefore, \( [\text{A}^{3+}] = 2S = 2.0 \times 10^{-5}\text{ M} \).
