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Physics · PYQ NEET UG 2016(2)
हिन्दीAn electron is moving in a circular path under the influence of a transverse magnetic field of \( 3.57 \times 10^{-2} \text{ T} \). If the value of \( e/m \) is \( 1.76 \times 10^{11} \text{ C/kg} \), the frequency of revolution of the electron is
Correct answer · Option 2
\( 1 \text{ GHz} \)
Explanation
Frequency \( f = \frac{qB}{2\pi m} = \frac{(e/m)B}{2\pi} = \frac{1.76 \times 10^{11} \times 3.57 \times 10^{-2}}{2 \times 3.14} \approx 1 \text{ GHz} \).
