A rectangular metal sheet has a length of \( 4.234 \text{ m} \), a breadth of \( 1.005 \text{ m} \), and a thickness of \( 2.01 \text{ cm} \). The total surface area of the sheet reported to appropriate significant figures is:

Thickness \( t = 2.01 \text{ cm} = 0.0201 \text{ m} \) has 3 significant figures. Total Surface Area \( A = 2(lb + bt + tl) = 2(4.25517 + 0.02020 + 0.08510) = 8.7209 \text{ m}^2 \). Since the minimum number of significant figures in the input measured data is 3 (in thickness), the final result must be rounded off to 3 significant figures, giving \( 8.72 \text{ m}^2 \).