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Physics · SYSTEMS OF PARTICLES AND ROTATIONAL MOTION
हिन्दीA car weighs \( 1800 \text{ kg} \). The distance between its front and back axles is \( 1.80 \text{ m} \). Its centre of gravity is \( 1.05 \text{ m} \) behind the front axle. Assuming \( g = 10 \text{ m s}^{-2} \), the normal force exerted by the level ground on each front wheel is:
Correct answer · Option 2
\( 3750 \text{ N} \)
Explanation
Total weight \( W = 1800 \times 10 = 18000 \text{ N} \). Taking torque about back axle: \( N_F (1.80) = W (1.80 - 1.05) = 18000 \times 0.75 \implies N_F = 7500 \text{ N} \) on both front wheels. Force on each front wheel is \( \frac{7500}{2} = 3750 \text{ N} \).
