OnlineCBT Logo OnlineCBT

Physics · PYQ NEET UG 2017

हिन्दी

A Carnot engine having an efficiency of \( \frac{1}{10} \) as heat engine, is used as a refrigerator. If the work done on the system is \( 10\text{ J} \), the amount of energy absorbed from the reservoir at lower temperature is:

  1. \( 1\text{ J} \)
  2. \( 90\text{ J} \)
  3. \( 99\text{ J} \)
  4. \( 100\text{ J} \)

Correct answer · Option 2

\( 90\text{ J} \)

Explanation

Coefficient of performance \( \beta = \frac{1 - \eta}{\eta} = \frac{1 - 1/10}{1/10} = 9 \). Also \( \beta = \frac{Q_2}{W} \implies Q_2 = \beta \times W = 9 \times 10 = 90\text{ J} \).
पता संपर्क करें

+91 7877547686

ई-मेल

onlinecbtportal@gmail.com

हेल्पलाइन नंबर

+91 7877547686


डाउनलोड करने के लिए क्लिक करें
Get it on Google Play

ऐप डाउनलोड करने
के लिए Google Play पर
उपलब्ध है

WhatsApp Chat