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Physics · PYQ NEET UG 2023

हिन्दी

In hydrogen spectrum, the shortest wavelength in the Balmer series is \( \lambda \). The shortest wavelength in the Bracket series is :

  1. \( 4\lambda \)
  2. \( 2\lambda \)
  3. \( 9\lambda \)
  4. \( 16\lambda \)

Correct answer · Option 4

\( 16\lambda \)

Explanation

For Balmer series, shortest wavelength \( \frac{1}{\lambda} = R(1/2^2 - 0) = \frac{R}{4} \Rightarrow \lambda = \frac{4}{R} \). For Brackett series, shortest wavelength \( \frac{1}{\lambda_B} = R(1/4^2 - 0) = \frac{R}{16} \Rightarrow \lambda_B = \frac{16}{R} = 4\lambda \).
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