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Physics · PYQ NEET UG 2016(2)

हिन्दी

A \( 100\ \Omega \) resistance and a capacitor of \( 100\ \Omega \) reactance are connected in series across a \( 220\text{V} \) source. When the capacitor is \( 50\% \) charged, the peak value of the displacement current is

  1. \( 11\sqrt{2} \text{ A} \)
  2. \( 2.2 \text{ A} \)
  3. \( 11 \text{ A} \)
  4. \( 4.4 \text{ A} \)

Correct answer · Option 2

\( 2.2 \text{ A} \)

Explanation

Impedance \( Z = \sqrt{R^2 + X_C^2} = \sqrt{100^2 + 100^2} = 100\sqrt{2}\ \Omega \). Peak source voltage \( V_0 = 220\sqrt{2}\text{ V} \). Peak current \( I_0 = \frac{V_0}{Z} = \frac{220\sqrt{2}}{100\sqrt{2}} = 2.2 \text{ A} \). Displacement current equals conduction current at all times.
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