OnlineCBT
Physics · WORK, ENERGY AND POWER
हिन्दीA heavy body of mass \( M \) moving with speed \( u \) collides elastically with a very light body of mass \( m \) (\( m \ll M \)) initially at rest. The speed of the lighter body after the collision is:
Correct answer · Option 4
\( 2u \)
Explanation
From elastic collision formula: \( v_{2f} = \frac{2M}{M + m}u \). Since \( m \ll M \), \( v_{2f} \approx \frac{2M}{M}u = 2u \).
