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Physics · PYQ NEET UG 2020
हिन्दीA body weighs \( 72\text{ N} \) on the surface of the earth. What is the gravitational force on it, at a height equal to half the radius of the earth?
Correct answer · Option 1
32 N
Explanation
Gravitational force varies with height as \( W' = W (\frac{R}{R + h})^2 \). Given \( h = R/2 \), so \( W' = 72 (\frac{R}{R + R/2})^2 = 72 (\frac{2}{3})^2 = 72 \times \frac{4}{9} = 32\text{ N} \).
