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Chemistry · PYQ NEET UG 2016(1)

हिन्दी

Which one of the following orders is CORRECT for the bond dissociation enthalpy of halogen molecules?

  1. \( \mathrm{Br}_2 > \mathrm{I}_2 > \mathrm{F}_2 > \mathrm{Cl}_2 \)
  2. \( \mathrm{F}_2 > \mathrm{Cl}_2 > \mathrm{Br}_2 > \mathrm{I}_2 \)
  3. \( \mathrm{Cl}_2 > \mathrm{Br}_2 > \mathrm{F}_2 > \mathrm{I}_2 \)
  4. \( \mathrm{I}_2 > \mathrm{Br}_2 > \mathrm{Cl}_2 > \mathrm{F}_2 \)

Correct answer · Option 3

\( \mathrm{Cl}_2 > \mathrm{Br}_2 > \mathrm{F}_2 > \mathrm{I}_2 \)

Explanation

Due to small size and high interelectronic repulsions in the lone pairs of \( \mathrm{F}_2 \), its bond dissociation enthalpy is unusually low. The correct order is \( \mathrm{Cl}_2 > \mathrm{Br}_2 > \mathrm{F}_2 > \mathrm{I}_2 \).
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