OnlineCBT
Chemistry · EQUILIBRIUM
हिन्दीConsider the following equilibria at a given temperature: (1) \( \text{N}_2(\text{g}) + 3\text{H}_2(\text{g}) \rightleftharpoons 2\text{NH}_3(\text{g}) \) with equilibrium constant \( K_1 \) (2) \( \text{N}_2(\text{g}) + \text{O}_2(\text{g}) \rightleftharpoons 2\text{NO}(\text{g}) \) with equilibrium constant \( K_2 \) (3) \( \text{H}_2(\text{g}) + \frac{1}{2}\text{O}_2(\text{g}) \rightleftharpoons \text{H}_2\text{O}(\text{g}) \) with equilibrium constant \( K_3 \) The equilibrium constant \( K \) for the reaction \( 2\text{NH}_3(\text{g}) + \frac{5}{2}\text{O}_2(\text{g}) \rightleftharpoons 2\text{NO}(\text{g}) + 3\text{H}_2\text{O}(\text{g}) \) is given by:
Correct answer · Option 1
\( \frac{K_2 K_3^3}{K_1} \)
Explanation
Target reaction = Reverse of reaction (1) + Reaction (2) + 3 × Reaction (3). Therefore, \( K = (\frac{1}{K_1}) \times K_2 \times (K_3)^3 = \frac{K_2 K_3^3}{K_1} \).
