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Chemistry · PYQ NEET UG 2021

हिन्दी

The molar conductance of \( \text{NaCl} \), \( \text{HCl} \) and \( \text{CH}_3\text{COONa} \) at infinite dilution are \( 126.45 \), \( 426.16 \) and \( 91.0 \text{ S cm}^2 \text{ mol}^{-1} \) respectively. The molar conductance of \( \text{CH}_3\text{COOH} \) at infinite dilution is. Choose the right option for answer. Which of the above statements is/are correct?

  1. \( 390.71 \text{ S cm}^2 \text{ mol}^{-1} \)
  2. \( 698.28 \text{ S cm}^2 \text{ mol}^{-1} \)
  3. \( 540.48 \text{ S cm}^2 \text{ mol}^{-1} \)
  4. \( 201.28 \text{ S cm}^2 \text{ mol}^{-1} \)

Correct answer · Option 1

\( 390.71 \text{ S cm}^2 \text{ mol}^{-1} \)

Explanation

By Kohlrausch's law: \( \Lambda_m^\infty(\text{CH}_3\text{COOH}) = \Lambda_m^\infty(\text{CH}_3\text{COONa}) + \Lambda_m^\infty(\text{HCl}) - \Lambda_m^\infty(\text{NaCl}) = 91.0 + 426.16 - 126.45 = 390.71 \text{ S cm}^2 \text{ mol}^{-1} \).
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