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Physics · GRAVITATION

हिन्दी

A body is projected vertically upwards from the surface of the Earth with a speed \( v_i = \sqrt{3} v_e \), where \( v_e \) is the escape speed from the Earth's surface. Its speed at an infinite distance from the Earth will be:

  1. \( \sqrt{2} v_e \)
  2. \( 2 v_e \)
  3. \( \sqrt{3} v_e \)
  4. \( (\sqrt{3} - 1) v_e \)

Correct answer · Option 1

\( \sqrt{2} v_e \)

Explanation

From energy conservation: \( \frac{1}{2}m v_i^2 - \frac{1}{2}m v_e^2 = \frac{1}{2}m v_\infty^2 \implies v_\infty = \sqrt{v_i^2 - v_e^2} = \sqrt{3 v_e^2 - v_e^2} = \sqrt{2} v_e \).
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