Physics · Electrostatic Potential
हिन्दीThe electric field just outside the surface of a charged conductor with local surface charge density \( \sigma \) is given by:
Correct answer · Option 2
\( \frac{\sigma}{\varepsilon_0}\mathbf{\hat{n}} \)
Explanation
Applying Gauss's law using a small pillbox spanning the surface gives flux E delta S = (sigma delta S)/eps0, hence E = (sigma/eps0) n_hat.