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Physics · Electrostatic Potential
हिन्दीA dielectric slab having electric susceptibility \( \chi_e = 3 \) is placed in a uniform external electric field \( E_0 \). What is the ratio of the net electric field \( E \) inside the slab to the external field \( E_0 \)?
Correct answer · Option 1
\( \frac{1}{4} \)
Explanation
The dielectric constant is \( K = 1 + \chi_e = 1 + 3 = 4 \). The net electric field inside is \( E = E_0/K = E_0/4 \), so \( E/E_0 = 1/4 \).
