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Chemistry · Structure of atom

हिन्दी

A microscope using suitable photons is employed to locate an electron in an atom within a distance of \( 0.1 \text{ \AA} \). What is the uncertainty involved in the measurement of its velocity (\( \Delta v \))?

  1. \( 9.11 \times 10^4 \text{ m s}^{-1} \)
  2. \( 1.15 \times 10^7 \text{ m s}^{-1} \)
  3. \( 2.89 \times 10^5 \text{ m s}^{-1} \)
  4. \( 5.79 \times 10^6 \text{ m s}^{-1} \)

Correct answer · Option 4

\( 5.79 \times 10^6 \text{ m s}^{-1} \)

Explanation

Using \( \Delta v = \frac{h}{4\pi m \Delta x} \) with \( \Delta x = 0.1 \text{ \AA} = 0.1 \times 10^{-10} \text{ m} \), we obtain \( \Delta v = 5.79 \times 10^6 \text{ m s}^{-1} \).
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