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Physics · PYQ NEET UG 2023
हिन्दीFor the following logic circuit, the truth table is:
Correct answer · Option 1
A B Y
0 0 1
0 1 1
1 0 1
1 1 0
Explanation
Inputs A and B pass through NOT gates (inverters), giving \( \bar{A} \) and \( \bar{B} \). These are connected to a NAND gate, so \( Y = \overline{\bar{A} \cdot \bar{B}} = A + B \) (by De Morgan's Law, which is equivalent to an OR gate). Checking the truth table for OR gate: 0,0->0; 0,1->1; 1,0->1; 1,1->1.
