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Chemistry · PYQ NEET UG 2016(1)
हिन्दीThe pressure of \( \text{H}_2 \) required to make the potential of \( \text{H}_2 \) electrode zero in pure water at \( 298\text{ K} \) is
Correct answer · Option 3
\( 10^{-14}\text{ atm} \)
Explanation
For \( E = 0 \) in pure water at \( pH = 7 \), Nernst equation gives \( E = 0 - \frac{0.0591}{2}\log(\frac{P_{\text{H}_2}}{[\text{H}^+]^2}) \). Since \( [\text{H}^+] = 10^{-7} \), \( P_{\text{H}_2} = 10^{-14}\text{ atm} \).
