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Physics · LAWS OF MOTION

हिन्दी

Three concurrent forces \( \mathbf{F}_1 \), \( \mathbf{F}_2 \), and \( \mathbf{F}_3 \) keep a particle in equilibrium. If \( \mathbf{F}_1 = 3\hat{i} - 4\hat{j}\text{ N} \) and \( \mathbf{F}_2 = -2\hat{i} + 6\hat{j}\text{ N} \), then the third force \( \mathbf{F}_3 \) is equal to:

  1. \( \hat{i} + 2\hat{j}\text{ N} \)
  2. \( -\hat{i} - 2\hat{j}\text{ N} \)
  3. \( -5\hat{i} - 2\hat{j}\text{ N} \)
  4. \( 5\hat{i} + 10\hat{j}\text{ N} \)

Correct answer · Option 2

\( -\hat{i} - 2\hat{j}\text{ N} \)

Explanation

For equilibrium, \( \mathbf{F}_1 + \mathbf{F}_2 + \mathbf{F}_3 = 0 \implies \mathbf{F}_3 = -(\mathbf{F}_1 + \mathbf{F}_2) = -((3-2)\hat{i} + (-4+6)\hat{j}) = -\hat{i} - 2\hat{j}\text{ N} \).
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