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Physics · GRAVITATION
हिन्दीAt what depth \( d \) below the surface of the Earth will the acceleration due to gravity become one-fourth of its value on the Earth's surface? (Assume the radius of Earth is \( R_E \))
Correct answer · Option 3
\( \frac{3R_E}{4} \)
Explanation
The acceleration due to gravity at depth \( d \) is \( g(d) = g(1 - d/R_E) \). Setting \( g(d) = g/4 \) gives \( 1 - d/R_E = 1/4 \implies d = 3R_E/4 \).
