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Physics · PYQ NEET UG 2016(2)
हिन्दीTwo cars P and Q start from a point at the same time in a straight line and their positions are represented by \( x_P(t) = at + bt^2 \) and \( x_Q(t) = ft - t^2 \). At what time do the cars have the same velocity?
Correct answer · Option 1
\( \frac{f-a}{2(1+b)} \)
Explanation
Velocities are \( v_P = \frac{dx_P}{dt} = a + 2bt \) and \( v_Q = \frac{dx_Q}{dt} = f - 2t \). Equating velocities: \( a + 2bt = f - 2t \implies 2t(1+b) = f - a \implies t = \frac{f-a}{2(1+b)} \).
